Django: Arbitrary number of unnamed urls.py parameters

Question

I have a Django model with a large number of fields and 20000+ table rows. To facilitate human readable URLs and the ability to break down the large list into arbitrary sub

Answer 1

I think the answer of Adam is more generic than my solution, but if you like to use a fixed number of arguments in the url, you could also do something like this:

The following example shows how to get all sales of a day for a location by entering the name of the store and the year, month and day.

urls.py:

urlpatterns = patterns('',
    url(r'^baseurl/location/(?P.+)/sales/(?P[0-9][0-9][0-9][0-9])-(?P[0-9][0-9])-(?P[0-9][0-9])/$', views.DailySalesAtLocationListAPIView.as_view(), name='daily-sales-at-location'),
)

Alternativly, you could also use the id of the store by changing (?P.+) to (?P[0-9]+). Note that location and sales are no keywords, they just improve readability of the url.

views.py

class DailySalesAtLocationListAPIView(generics.ListAPIView):
    def get(self, request, store, year, month, day):
        # here you can start using the values from the url
        print store
        print year
        print month
        print date

        # now start filtering your model

Hope it helps anybody!

Best regards,

Michael