How to get only part of URL from HttpServletRequest?

Question

From the following URL I need to get (http://localhost:9090/dts) alone.
That is I need to remove (documents/savedoc) (OR)
need to get on

Answer 1

Usually I have a method like this:

public String getAbsoluteContextPath() throws MalformedURLException {
    ExternalContext context = FacesContext.getCurrentInstance().getExternalContext();
    HttpServletRequest request = (HttpServletRequest) context.getRequest();
    URL url = new URL(request.getRequestURL().toString());
    return url.getProtocol() + "://" + url.getAuthority() + context.getRequestContextPath();
}

This method will return what you want, with the port number only if it exists in the current request. In your case it will return: http://localhost:9090/dts