How to get only part of URL from HttpServletRequest?

Question

From the following URL I need to get (http://localhost:9090/dts) alone.
That is I need to remove (documents/savedoc) (OR)
need to get on

Answer 1

In my understanding, you need the domain part and Context path only. Based on this understanding, You can use this method to get the required string.

String domain = request.getRequestURL().toString();
String cpath = request.getContextPath().toString();

String tString = domain.subString(0, domain.indexOf(cpath));

tString = tString + cpath;