Haskell replace element in list

Question

Is there any built-in function to replace an element at a given index in haskell?

Example:

replaceAtIndex(2,\"foo\",[\"bar\",\"bar\",\"bar\"])

Answer 1

Try this solution:

import Data.List

replaceAtIndex :: Int -> a -> [a] -> [a]    
replaceAtIndex i x xs = take i xs ++ [x] ++ drop (i+1) xs

It works as follows:

get the first i items, add the value 'x', add the rest of i+1 items