Haskell replace element in list

Question

Is there any built-in function to replace an element at a given index in haskell?

Example:

replaceAtIndex(2,\"foo\",[\"bar\",\"bar\",\"bar\"])

Answer 1

There is actual arrays, but lists are really singly linked lists and the notion of replacing an element is not quite as obvious (and accessing an element at a given index may indicate that you shouldn't be using a list, so operations that might encourage it are avoided).