Is there a way to find if the XCUIElement has focus or not?

Question

One of my screen has multiple text fields, I can land to this screen from different other screens. In each case I am making one or another text field as first responder. I a

Answer 1

I little bit late for the party :) However as far as I can see from dumping the variable XCUIElement it has one interesting property:

property name: hasKeyboardFocus

property type: TB,R

So you can check if your element has focus the following way:

let hasFocus = (yourTextField.value(forKey: "hasKeyboardFocus") as? Bool) ?? false

NB: you can dump the property variables of any NSObject sublass with following extension:

extension NSObject {
    func dumpProperties() {
        var outCount: UInt32 = 0

        let properties = class_copyPropertyList(self.dynamicType, &outCount)
        for index in 0...outCount {
            let property = properties[Int(index)]
            if nil == property {
                continue
            }
            if let propertyName = String.fromCString(property_getName(property)) {
                print("property name: \(propertyName)")
            }
            if let propertyType = String.fromCString(property_getAttributes(property)) {
                print("property type: \(propertyType)")
            }
        }
    }
}

Update: Properties dump, Swift 4:*

extension NSObject {
    func dumpProperties() {
        var outCount: UInt32 = 0

        let properties = class_copyPropertyList(type(of: self), &outCount)
        for index in 0...outCount {
            guard let property = properties?[Int(index)] else {
                continue
            }
            let propertyName = String(cString: property_getName(property))
            print("property name: \(propertyName)")
            guard let propertyAttributes = property_getAttributes(property) else {
                continue
            }
            let propertyType = String(cString: propertyAttributes)
            print("property type: \(propertyType)")
        }
    }
}