Why does (int)55 == 54 in C++?

Question

So I\'m learning C++. I\'ve got my \"C++ Programming Language\" and \"Effective C++\" out and I\'m running through Project Euler. Problem 1...dunzo. Problem 2...not so mu

Answer 1

Casting to int truncates the number - same as if you'd called floor(currentFib). So even if currentFib is 54.999999... (a number so close to 55 that it will be rounded up when printed), (int)currentFib will produce 54.