Launch App using URL, but OpenUrl Not Called

Question

I have implemented a URL Scheme and use it to pass data to my app by calling method. The entire code is shown as below

- (BOOL)application:(UIApplication *)a         


        

Answer 1

I agree with Kaloyan, "handleOpenURL" is never called at application launch. So you have to check for URL in "launchOptions" in didFinishLaunchingWithOptions.

HOWEVER

I adopted the same solution as Apple example code for QuickActions (3D Touch). I keep the URL at launch in a variable, and I handle it in applicationDidBecomeActive:.

@interface MyAppDelegate ()
@property (nonatomic, strong) NSURL *launchedURL;
@end

@implementation MyAppDelegate

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
{
    self.launchedURL = [launchOptions objectForKey:UIApplicationLaunchOptionsURLKey];
    ...
}

- (void)applicationDidBecomeActive:(UIApplication *)application
{
    if (self.launchedURL) {
        [self openLink:self.launchedURL];
        self.launchedURL = nil;
    }
}

- (BOOL)  application:(UIApplication *)application
          openURL:(NSURL *)url
sourceApplication:(NSString *)sourceApplication
       annotation:(id)annotation
{
    NSURL *openUrl = url;

    if (!openUrl)
    {
        return NO;
    }
    return [self openLink:openUrl];
}

- (BOOL)openLink:(NSURL *)urlLink
{
    ...
}

@end