How to sort one list based on another? [duplicate]

Answer 1

I think this answers your question:

>>> [x for x in Ref if x in Input]
>>> [3, 2, 11, 10, 9, 8, 5, 4]

Hope it helps.

UPDATE: Making Input a set for faster access:

>>> Input_Set = set(Input)
>>> [x for x in Ref if x in Input_Set]
[3, 2, 11, 10, 9, 8, 5, 4]