Invoke Operator & Operator Overloading in Kotlin

Question

I get to know about the Invoke operator that,

a() is equivalent to a.invoke()

Is there anything more regarding Invoke operator the

Answer 1

If you have some Python background,

you can think invoke in Kotlin as __call__ in Python.

By using this, you can "call" your object as if it's a function.

One difference is: you can overload invoke, but there is no official way to overload methods in Python.