Iterating through a range of ints in ksh?

Question

How can I iterate through a simple range of ints using a for loop in ksh?

For example, my script currently does this...

for i in 1 2 3 4 5 6 7
do
            


        

Answer 1

Just a few examples I use in AIX because there is no range operator or seq, abusing perl instead.

Here's a for loop, using perl like seq:

for X in `perl -e 'print join(" ", 1..10)'` ; do something $X ; done

This is similar, but I prefer while read loops over for. No backticks or issues with spaces.

perl -le 'print "$_ " for 1..10;' | while read X ; do xargs -tn1 ls $X ; done

My fav, do bash-like shell globbing, in this case permutations with perl.

perl -le 'print for glob "e{n,nt,t}{0,1,2,3,4,5}"' | xargs -n1 rmdev -dl