Bash - how to put each line within quotation

Question

I want to put each line within quotation marks, such as:

abcdefg
hijklmn
opqrst

convert to:

\"abcdefg\"
\"hijklmn\"
\"opqrs         


        

Answer 1

I used sed with two expressions to replace start and end of line, since in my particular use case I wanted to place HTML tags around only lines that contained particular words.

So I searched for the lines containing words contained in the bla variable within the text file inputfile and replaced the beginnign with

and the end with

(well actually I did some longer HTML tagging in the real thing, but this will serve fine as example)

Similar to:

$ bla=foo
$ sed -e "/${bla}/s#^#
#" -e "/${bla}/s#\$#
#" inputfile
foo
bar
$