Bash - how to put each line within quotation

Question

I want to put each line within quotation marks, such as:

abcdefg
hijklmn
opqrst

convert to:

\"abcdefg\"
\"hijklmn\"
\"opqrs         


        

Answer 1

I use the following command:

xargs -I{lin} echo \"{lin}\" < your_filename

The xargs take standard input (redirected from your file) and pass one line a time to {lin} placeholder, and then execute the command at next, in this case a echo with escaped double quotes.

You can use the -i option of xargs to omit the name of the placeholder, like this:

xargs -i echo \"{}\" < your_filename

In both cases, your IFS must be at default value or with '\n' at least.