Bash - how to put each line within quotation

Question

I want to put each line within quotation marks, such as:

abcdefg
hijklmn
opqrst

convert to:

\"abcdefg\"
\"hijklmn\"
\"opqrs         


        

Answer 1

Using awk

awk '{ print "\""$0"\""}' inputfile

Using pure bash

while read FOO; do
   echo -e "\"$FOO\""
done < inputfile

where inputfile would be a file containing the lines without quotes.

If your file has empty lines, awk is definitely the way to go:

awk 'NF { print "\""$0"\""}' inputfile

NF tells awk to only execute the print command when the Number of Fields is more than zero (line is not empty).