Python find first instance of non zero number in list

Question

I have a list like this

myList = [0.0 , 0.0, 0.0, 2.0, 2.0]

I would like to find the location of the first number in the list that is not e

Answer 1

What about using enumerate? Check the enumerate documentation.

def first_non_zero(mylist):
  for index, number in enumerate(mylist):
    if number != 0: # or 'if number:'
      return index