Python find first instance of non zero number in list

Question

I have a list like this

myList = [0.0 , 0.0, 0.0, 2.0, 2.0]

I would like to find the location of the first number in the list that is not e

Answer 1

Using next with enumerate is excellent when the array is large. For smaller arrays, I would use argmax from numpy so that you won't need a loop:

import numpy as np

myList = [0.0, 0.0, 0.0, 2.0, 2.0]
myArray = np.array(myList)
np.argmax(myArray > 0)
3