Python find first instance of non zero number in list

Question

I have a list like this

myList = [0.0 , 0.0, 0.0, 2.0, 2.0]

I would like to find the location of the first number in the list that is not e

Answer 1

Use next with enumerate:

>>> myList = [0.0 , 0.0, 0.0, 2.0, 2.0]
>>> next((i for i, x in enumerate(myList) if x), None) # x!= 0 for strict match
3