Comparison operator overloading

Question

Which is best practice (in this case):

bool Foo::operator==(const Foo& other) {
  return bar == other.bar;
}

// Implementation 1
bool Foo::operator!=(co         


        

Answer 1

In general, implementation 2 is better for many reasons. First of all, you don't write (almost) duplicate code. If you need to change it (because the class has grown or there has been a bug), again with implementation 2 you change only 1 place. That is, implementation 2 makes your code more consistent and less error prone.