Comparison operator overloading

Question

Which is best practice (in this case):

bool Foo::operator==(const Foo& other) {
  return bar == other.bar;
}

// Implementation 1
bool Foo::operator!=(co         


        

Answer 1

The second implementation has the notable constraint that == will always be the boolean opposite of !=. This is probably what you want, and it makes your code easier to maintain because you only have to change one implementation to keep the two in sync.