Operator precedence in c with pointers

Question

How to analyse the precedence in following situation .

for (i=0; i<20; i++)
{
    *array_p++ = i*i;
    printf(\"%d\\n\",*arr++);
}

how

Answer 1

In the first sample code snippet,

    for (i=0; i<20; i++)
        {
          *array_p++ = i*i;
           printf("%d\n",*arr++);
    }

array_ptr is incremented first i.e address, and then the value computed from i*i is assigned to *array_ptr since evaluation takes in the order of right to left i.e *(array_ptr ++).

In the second sample of code snippet,

for (int i=0; i<20; i++)
{
  *arr = i*i;
printf("%d\n",*arr);
 arr++; 
printf("%d\n",(int )arr);
}

value computed from i*i is first computed and assigned to *arr, then pointer pointing to arr is incremented.

Hence there is difference in values among the 2 code snippets.