Operator precedence in c with pointers

Question

How to analyse the precedence in following situation .

for (i=0; i<20; i++)
{
    *array_p++ = i*i;
    printf(\"%d\\n\",*arr++);
}

how

Answer 1

Citing Wikipedia, postfix ++ binds before unary *. This means that you have *(arr++). For example, in the expression *arr++ = 5, *arr is assigned to 5, then arr is incremented.

In the K&R, this trick is used to write a concise version of memcpy. It's something like:

while (--size)
    *dest++ = *src++;

I'll post the correct example after I get home tonight.

Edit: Apparently, only postfix ++ has higher precedence. Wikipedia says prefix ++ has equal precedence.