Java: Longest common subsequence

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谎友^
谎友^ 2020-12-30 18:27

I have following code:

public class LCS1 {

    public static String lcs(String a, String b) {
        String x;
        String y;

        int alen = a.leng         


        
3条回答
  •  挽巷
    挽巷 (楼主)
    2020-12-30 18:38

    public static String longestSubstring(String str1, String str2) {
    
        StringBuilder sb = new StringBuilder();
        if (str1 == null || str1.isEmpty() || str2 == null || str2.isEmpty())
            return "";
    
        // ignore case
        str1 = str1.toLowerCase();
        str2 = str2.toLowerCase();
    
        // java initializes them already with 0
        int[][] num = new int[str1.length()][str2.length()];
        int maxlen = 0;
        int lastSubsBegin = 0;
    
        for (int i = 0; i < str1.length(); i++) {
            for (int j = 0; j < str2.length(); j++) {
                if (str1.charAt(i) == str2.charAt(j)) {
                    if ((i == 0) || (j == 0))
                        num[i][j] = 1;
                    else
                        num[i][j] = 1 + num[i - 1][j - 1];
    
                    if (num[i][j] > maxlen) {
                        maxlen = num[i][j];
                        // generate substring from str1 => i
                        int thisSubsBegin = i - num[i][j] + 1;
                        if (lastSubsBegin == thisSubsBegin) {
                            // if the current LCS is the same as the last time
                            // this block ran
                            sb.append(str1.charAt(i));
                        } else {
                            // this block resets the string builder if a
                            // different LCS is found
                            lastSubsBegin = thisSubsBegin;
                            sb = new StringBuilder();
                            sb.append(str1.substring(lastSubsBegin, i + 1));
                        }
                    }
                }
            }
        }
    
        return sb.toString();
    }
    

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