How can I select the record with the 2nd highest salary in database Oracle?

Question

Suppose I have a table employee with id, user_name, salary. How can I select the record with the 2nd highest salary in Oracle?

I googled it, find this solution, is t

Answer 1

select * FROM (
select EmployeeID, Salary
, dense_rank() over (order by Salary DESC) ranking
from Employee
)
WHERE ranking = 2;

dense_rank() is used for the salary has to be same.So it give the proper output instead of using rank().