Please explain the difference

Question

i have a program about 2-D arrays

base adress is 8678

#include
#include
         


        

Answer 1

You can figure this out with the help of this equivalence: X[Y] === *(X+Y)

Since *(arr+1) === arr[1], arr+1 === &arr[1]

Similarly, &arr+1 === &((&arr)[1])

What is (&arr)[1]? Well, (&arr)[0] === *&arr === arr, that is, the 3x3 array itself, so (&arr)[1] is the 3x3 array following that, and &arr+1 === &((&arr)[1]) is the address of the 3x3 array following &arr ... a pointer to the byte just past the entire array.