How do I create a zip file of a file path using Python, including empty directories?

Question

I\'ve been trying to use the zipfile and shutil.make_archive modules to recursively create a zip file of a directory. Both modules work great--exc

Answer 1

There is a example using zipfile:

import os, zipfile  
from os.path import join  
def zipfolder(foldername, filename, includeEmptyDIr=True):   
    empty_dirs = []  
    zip = zipfile.ZipFile(filename, 'w', zipfile.ZIP_DEFLATED)  
    for root, dirs, files in os.walk(foldername):  
        empty_dirs.extend([dir for dir in dirs if os.listdir(join(root, dir)) == []])  
        for name in files:  
            zip.write(join(root ,name))  
        if includeEmptyDIr:  
            for dir in empty_dirs:  
                zif = zipfile.ZipInfo(join(root, dir) + "/")  
                zip.writestr(zif, "")  
        empty_dirs = []  
    zip.close() 

if __name__ == "__main__":
    zipfolder('test1/noname/', 'zip.zip')