How to find N Consecutive records in a table using SQL

Question

I have the following Table definition with sample data. In the following table, Customer Product & Date are key fields

Table One
Customer   Product    Da         


        

Answer 1

Thanks to everyone for posting your solution. Thought, I would also share my solution with everyone. Just as an FYI, I received this solution from another SQL Server Central forum member. I am definitely not going to take credit for this solution.

DECLARE @CNT INT
SELECT @CNT = 3

SELECT * FROM
(
  SELECT
    [Customer], [Product], [Date], [Sale], groupID, 
    COUNT(*) OVER (PARTITION BY [Customer], [Product], [Sale], groupID) AS groupCnt
  FROM
  (
    SELECT
      [Customer], [Product], [Date], [Sale],
      ROW_NUMBER() OVER (PARTITION BY [Customer], [Product] ORDER BY [Date])
      - ROW_NUMBER() OVER (PARTITION BY [Customer], [Product], [Sale] ORDER BY [Date]) AS groupID
    FROM
      [TableSales]
  ) T1
) T2
WHERE
  T2.[Sale] = 'NO' AND T2.[groupCnt] >= @CNT