Most elegant way to detect if a String is a number?

Question

Is there a better, more elegant (and/or possibly faster) way than

boolean isNumber = false;
try{
   Double.valueOf(myNumber);
   isNumber = true;
} catch (Nu         


        

Answer 1

Leveraging off Mr. Skeet:

private boolean IsValidDoubleChar(char c)
{
    return "0123456789.+-eE".indexOf(c) >= 0;
}

public boolean isDouble(String value)
{
    for (int i=0; i < value.length(); i++)
    {
        char c = value.charAt(i);
        if (IsValidDoubleChar(c))
            continue;
        return false;
    }
    try
    {
        Double.parseDouble(value);
        return true;
    }
    catch (NumberFormatException e)
    {
        return false;
    }
}