class, dict, self, init, args?

Question

class attrdict(dict):
    def __init__(self, *args, **kwargs):
        dict.__init__(self, *args, **kwargs)
        self.__dict__ = self

a = attrdict(x=1, y=2)
prin         


        

Answer 1

You are not using positional arguments in your example. So the relevant code is:

class attrdict(dict):
    def __init__(self, **kwargs):
        dict.__init__(self, **kwargs)
        self.__dict__ = self

In the first line you define class attrdict as a subclass of dict. In the second line you define the function that automatically will initialize your instance. You pass keyword arguments (**kargs) to this function. When you instantiate a:

 a = attrdict(x=1, y=2)

you are actually calling

attrdict.__init__(a, {'x':1, 'y':2})

dict instance core initialization is done by initializing the dict builtin superclass. This is done in the third line passing the parameters received in attrdict.__init__. Thus,

dict.__init__(self,{'x':1, 'y':2})

makes self (the instance a) a dictionary:

self ==  {'x':1, 'y':2}

The nice thing occurs in the last line: Each instance has a dictionary holding its attributes. This is self.__dict__ (i.e. a.__dict__).

For example, if

a.__dict__ = {'x':1, 'y':2} 

we could write a.x or a.y and get values 1 or 2, respectively.

So, this is what line 4 does:

self.__dict__ = self

is equivalent to:

a.__dict__ = a  where a = {'x':1, 'y':2}

Then I can call a.x and a.y.

Hope is not too messy.