Printing the hexadecimal representation of a char array[]

Question

I\'ve got an array of 8 bytes that I\'m trying to print out the hexadecimal notation for. Using printf(\"%x\", array) I can get at the first byte and print it

Answer 1

This is what I did, its a little bit easier with a function and I use for debugging and logging memory.

void print_hex_memory(void *mem) {
  int i;
  unsigned char *p = (unsigned char *)mem;
  for (i=0;i<128;i++) {
    printf("0x%02x ", p[i]);
    if ((i%16==0) && i)
      printf("\n");
  }
  printf("\n");
}