PHP preg_replace three times with three different patterns? right or wrong?

Question

A simple question: Is this the best way to do it?

$pattern1 = \"regexp1\";
$pattern2 = \"regexp2\";
$pattern3 = \"regexp3\";

$content = preg_replace($patter         


        

Answer 1

A very readable approach is to make an array with patterns and replacements, and then use array_keys and array_values in the preg_replace

$replace = [
   "1" => "one",
   "2" => "two",
   "3" => "three"
];
$content = preg_replace( array_keys( $replace ), array_values( $replace ), $content );

This even works with more complex patterns. The following code will replace 1, 2 and 3, and it will remove double spaces.

$replace = [
   "1"       => "one",
   "2"       => "two",
   "3"       => "three",
   "/ {2,}/" => " "
];
$content = preg_replace( array_keys( $replace ), array_values( $replace ), $content );