Find all list permutations of splitting a string in Python

Question

I have a string of letters that I\'d like to split into all possible combinations (the order of letters must be remain fixed), so that:

s = \'monkey\'
         


        

Answer 1

http://wordaligned.org/articles/partitioning-with-python contains an interesting post about sequence partitioning, here is the implementation they use:

#!/usr/bin/env python

# From http://wordaligned.org/articles/partitioning-with-python

from itertools import chain, combinations

def sliceable(xs):
    '''Return a sliceable version of the iterable xs.'''
    try:
        xs[:0]
        return xs
    except TypeError:
        return tuple(xs)

def partition(iterable):
    s = sliceable(iterable)
    n = len(s)
    b, mid, e = [0], list(range(1, n)), [n]
    getslice = s.__getitem__
    splits = (d for i in range(n) for d in combinations(mid, i))
    return [[s[sl] for sl in map(slice, chain(b, d), chain(d, e))]
            for d in splits]

if __name__ == '__main__':
    s = "monkey"
    for i in partition(s):
        print i

Which would print:

['monkey']
['m', 'onkey']
['mo', 'nkey']
['mon', 'key']
['monk', 'ey']
['monke', 'y']
['m', 'o', 'nkey']
['m', 'on', 'key']
['m', 'onk', 'ey']
['m', 'onke', 'y']
['mo', 'n', 'key']
['mo', 'nk', 'ey']
['mo', 'nke', 'y']
['mon', 'k', 'ey']
['mon', 'ke', 'y']
['monk', 'e', 'y']
...
['mo', 'n', 'k', 'e', 'y']
['m', 'o', 'n', 'k', 'e', 'y']