Converting an OpenCV BGR 8-bit Image to CIE L*a*b*

Question

I am trying to convert a given Mat representing an RGB image with 8-bit depth to Lab using the function provided in the documentation:

Answer 1

If anyone is interested in the range of the other variables a and b I made a small program to test their range. If you convert all the colors that are represented with RGB to the CieLab used in OpenCV the ranges are:

0  <=L<= 255
42 <=a<= 226
20 <=b<= 223

And if you're using RGB values in the float mode instead of uint8 the ranges will be:

0.0      <=L<= 100.0
-86.1813 <=a<= 98.2352
-107.862 <=b<= 94.4758

P.S. If you want to see how distinguishable (regarding human perception) is a LAB value from another LAB value, you should use the floating point. The scale used to keep the lab values in the uint8 ranges messes up with their euclidean distance.

This is the code I used (python):

L=[0]*256**3
a=[0]*256**3
b=[0]*256**3
i=0
for r in xrange(256):
    for g in xrange(256):
        for bb in xrange(256):
            im = np.array((bb,g,r),np.uint8).reshape(1,1,3)
            cv2.cvtColor(im,cv2.COLOR_BGR2LAB,im) #tranform it to LAB 
            L[i] = im[0,0,0]
            a[i] = im[0,0,1]
            b[i] = im[0,0,2]
            i+=1

print min(L), '<=L<=', max(L)
print min(a), '<=a<=', max(a)
print min(b), '<=b<=', max(b)