Return just the last day of each month with SQL

Question

I have a table that contains multiple records for each day of the month, over a number of years. Can someone help me out in writing a query that will only return the last d

Answer 1

Here's how I just solved this. day_date is the date field, calendar is the table that holds the dates.

SELECT cast(datepart(year, day_date) AS VARCHAR) 
+ '-' 
+ cast(datepart(month, day_date) AS VARCHAR) 
+ '-' 
+ cast(max(DATEPART(day, day_date)) AS VARCHAR) 'DATE'
FROM calendar
GROUP BY datepart(year, day_date)
    ,datepart(month, day_date)
ORDER BY 1