Truncate number of digit of double value in C#

Question

How can i truncate the leading digit of double value in C#,I have tried Math.Round(doublevalue,2) but not giving the require result. and i didn\'t find any other method in M

Answer 1

double original = 12.123456789;  

double truncated = Truncate(original, 2);  

Console.WriteLine(truncated.ToString());
// or 
// Console.WriteLine(truncated.ToString("0.00"));
// or 
// Console.WriteLine(Truncate(original, 2).ToString("0.00"));


public static double Truncate(double value, int precision)
{
    return Math.Truncate(value * Math.Pow(10, precision)) / Math.Pow(10, precision);
}