How to convert int* to int

Question

Given a pointer to int, how can I obtain the actual int?

I don\'t know if this is possible or not, but can someone please advise me?

Answer 1

int Array[10];

int *ptr6 = &Array[6];
int *ptr0 = &Array[0];

uintptr_t int_adress_6  = reinterpret_cast (ptr6);
uintptr_t int_adress_0  = reinterpret_cast (ptr0);

cout << "difference of casted addrs  = " << int_adress_6 - int_adress_0 << endl;  //24 bits

cout << "difference in integer = " << ptr6 - ptr0 << endl; //6