Why doesn't Integer.parseInt(“1”)++ work in Java?

Question

I\'ve got the following line of code:

suffix = suffix.isEmpty() ? \"1\" : Integer.toString(Integer.parseInt(suffix)+1);

in a block where su

Answer 1

Writing i++ is a shortcut for i=i+1; if you were to 'read it in english' you'd read it as "i becomes current value of i plus one"

which is why 3++ doesn't make sense you can't really say 3 = 3+1 (read as 3 becomes current value of 3 plus one) :-)