Shortest way to get an Iterator over a range of Integers in Java

Question

What\'s the shortest way to get an Iterator over a range of Integers in Java? In other words, implement the following:

/** 
* Returns an Iterator over the in         


        

Answer 1

A sample using stream API in java 8:

int first = 0;
int count = 10;
Iterator it = IntStream.range(first, first + count).iterator();
while (it.hasNext()) {
    System.out.println(it.next());
}

Without iterator, it could be:

int first = 0;
int count = 10;
IntStream.range(first, first + count).forEach(i -> System.out.println(i));