Shortest way to get an Iterator over a range of Integers in Java

Question

What\'s the shortest way to get an Iterator over a range of Integers in Java? In other words, implement the following:

/** 
* Returns an Iterator over the in         


        

Answer 1

This implementation does not have a memory footprint.

/**
 * @param begin inclusive
 * @param end exclusive
 * @return list of integers from begin to end
 */
public static List range(final int begin, final int end) {
    return new AbstractList() {
            @Override
            public Integer get(int index) {
                return begin + index;
            }

            @Override
            public int size() {
                return end - begin;
            }
        };
}

Edit:

In Java 8 you can simply say:

IntStream.range(begin, end).iterator()                // returns PrimitiveIterator.OfInt

or if you need the boxed version:

IntStream.range(begin, end).boxed().iterator()        // returns Iterator