Is there a Python equivalent of the Haskell 'let'

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青春惊慌失措
青春惊慌失措 2020-12-29 21:38

Is there a Python equivalent of the Haskell \'let\' expression that would allow me to write something like:

list2 = [let (name,size)=lookup(productId) in (ba         


        
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  •  悲&欢浪女
    2020-12-29 22:16

    You could use a temporary list comprehension

    [(barcode(productId), metric(size)) for name, size in [lookup(productId)]][0]
    

    or, equivalently, a generator expression

    next((barcode(productId), metric(size)) for name, size in [lookup(productId)])
    

    but both of those are pretty horrible.

    Another (horrible) method is via a temporary lambda, which you call immediately

    (lambda (name, size): (barcode(productId), metric(size)))(lookup(productId))
    

    I think the recommended "Pythonic" way would just be to define a function, like

    def barcode_metric(productId):
       name, size = lookup(productId)
       return barcode(productId), metric(size)
    list2 = [barcode_metric(productId) for productId in list]
    

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