I have the following object model in my Spring MVC (v3.2.0.RELEASE) web application:
public class Order {
private Payment payment;
}
@JsonTypeInfo(use = J
The method registerSubtypes() works!
@JsonTypeInfo(use=JsonTypeInfo.Id.NAME, include=JsonTypeInfo.As.PROPERTY, property="type")
public interface Geometry {
//...
}
public class Point implements Geometry{
//...
}
public class Polygon implements Geometry{
//...
}
public class LineString implements Geometry{
//...
}
GeoJson geojson= null;
ObjectMapper mapper = new ObjectMapper();
mapper.disable(DeserializationConfig.Feature.FAIL_ON_UNKNOWN_PROPERTIES);
mapper.registerSubtypes(Polygon.class,LineString.class,Point.class);
try {
geojson=mapper.readValue(source, GeoJson.class);
} catch (IOException e) {
e.printStackTrace();
}
Note1: We use the Interface and the implementing classes. I fyou want jackson to de-serialize the classes as per their implementing classes, you have to register all of them using ObjectMapper's "registerSubtypes" method.
Note2: In addition you use, " @JsonTypeInfo(use=JsonTypeInfo.Id.NAME, include=JsonTypeInfo.As.PROPERTY, property="type")" as annotation with your Interface.
You can also define the order of properties when mapper writes a value of your POJO as a json.
This you can do using below annotation.
@JsonPropertyOrder({"type","crs","version","features"})
public class GeoJson {
private String type="FeatureCollection";
private List features;
private String version="1.0.0";
private CRS crs = new CRS();
........
}
Hope this helps!