reversing the order of an array in ruby

Question

I have the following array [12,16,5,9,11,5,4] it prints: 12,16,5,9,11,5,4.

I want it to print: 4,5,11,9,5,16,12

When I

Answer 1

arr1 = [12,16,5,9,11,5,4]

i = 0
arr2 = []

arr1.length.times do
  arr2 << arr1.reverse[i]
  i += 1
end

p arr2

>>[4, 5, 11, 9, 5, 16, 12]