socket connection code of php

Question

I am writing a simple php socket code.
Here is my code

Answer 1

That is the expected behaviour of waiting. The program you have written is a socket server which is ready to listen to the connection with the specified port, until then it will wait.

You can create a client who connects so that you will see the response "Client is here". The client can be any programming language including PHP.

Below is a sample code in PHP (I didn't verify it).

$fp = stream_socket_client("127.0.0.1:9875", $errno, $errstr);

if (!$fp) {
    echo "$errstr ($errno)
\n";
} else {
   // Handle code here for reading/writing
}

You can check this link for sample client code in PHP.

EDIT

$host = "127.0.0.1";
$port = 9875;
$timeout = 30;
$sk = fsockopen($host, $port, $errnum, $errstr, $timeout);
if (!is_resource($sk)) {
    exit("connection fail: " . $errnum . " " . $errstr);
} else {
    echo "Connected";
}