Run PHP function inside Bash (and keep the return in a bash variable)

Question

I am trying to run a PHP function inside Bash... but it is not working.

#! /bin/bash

/usr/bin/php << \'EOF\'

EOF
         


        

Answer 1

This is how you can inline PHP commands within the shell i.e. *sh:

#!/bin/bash

export VAR="variable_value"
php_out=$(php << 'EOF'

EOF)
>&2 echo "php_out: $php_out"; #output