Virtual inheritance and static inheritance - mixing in C++

Question

If you have something like this:

#include 

template class A
{
public:
    void func()
    {
        T::func();
    }
};

c         


        

Answer 1

Seems you just had to add a little trace and usage to answer your own question...

#include 

template struct A { 
    void func() { 
        T::func(); 
    } 
}; 

struct B1 : A { 
    virtual void func() { 
        std::cout << "virtual void B1::func();\n";
    } 
}; 

struct B2 : A { 
    void func() { 
        std::cout << "void B2::func();\n";
    } 
}; 

struct C1 : B1 { }; 
struct C2 : B2 { }; 

struct C1a : B1 {
    virtual void func() {
        std::cout << "virtual void C1a::func();\n";
    }
};

struct C2a : B2 {
    virtual void func() {
        std::cout << "virtual void C2a::func();\n";
    }
};

int main()
{
    C1 c1; 
    c1.func(); 

    C2 c2; 
    c2.func(); 

    B1* p_B1 = new C1a;
    p_B1->func();

    B2* p_B2 = new C2a;
    p_B2->func();
}

Output:

virtual void B1::func();
void B2::func();
virtual void C1a::func();
void B2::func();

Conclusion: A does take on the virtual-ness of B's func.