Displaying a form from a dynamically loaded DLL

Question

This is an extension of a question I previously asked here.

Long story short, I dynamically load a DLL and make a type out of it with the following code:

Answer 1

I would go with:

Assembly assembly = Assembly.LoadFile("C:\\test.dll");
Type type = assembly.GetType("test.dllTest");
object obj = Activator.CreateInstance(type);
Form form = obj as Form;
if (form != null)
    form.Show(); //or ShowDilaog() whichever is needed

Other error checking/handling should be added; however at the very least I would ensure the conversion works.