Displaying a form from a dynamically loaded DLL

Question

This is an extension of a question I previously asked here.

Long story short, I dynamically load a DLL and make a type out of it with the following code:

Answer 1

You have to do something with the form you've just created:

Assembly assembly = Assembly.LoadFile("C:\\test.dll");
Type type = assembly.GetType("test.dllTest");
Form form = (Form)Activator.CreateInstance(type);
form.ShowDialog(); // Or Application.Run(form)