Simple way to group items into buckets

Question

I often want to bucket an unordered collection in python. itertools.groubpy does the right sort of thing but almost always requires massaging to sort the items first and cat

Answer 1

Edit:

Using DSM's answer as a start, here is a slightly more concise, general answer:

d = defaultdict(list)
map(lambda x: d[x in 'aeiou'].append(x),'thequickbrownfoxjumpsoverthelazydog')

or

d = defaultdict(list)
map(lambda x: d[x %10].append(x),xrange(21))

#

Here is a two liner:

d = {False:[],True:[]}
filter(lambda x: d[True].append(x) if x in 'aeiou' else d[False].append(x),"thequickbrownfoxjumpedoverthelazydogs")

Which can of course be made a one-liner:

d = {False:[],True:[]};filter(lambda x: d[True].append(x) if x in 'aeiou' else d[False].append(x),"thequickbrownfoxjumpedoverthelazydogs")