Simple way to group items into buckets

Question

I often want to bucket an unordered collection in python. itertools.groubpy does the right sort of thing but almost always requires massaging to sort the items first and cat

Answer 1

Here is a simple two liner

d = {}
for x in "thequickbrownfoxjumpsoverthelazydog": d.setdefault(x in 'aeiou', []).append(x)

Edit:

Just adding your other case for completeness.

d={}
for x in xrange(21): d.setdefault(x%10, []).append(x)