How do I set a EditText to the input of only hexadecimal numbers?

Question

I would put in this code a control on EditText so that it only accepts hexadecimal numbers. How do I go about doing this?

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Answer 1

There are two options, one is described by Muhammad Annaqeeb using the properties:

other option would be using an InputFilter and REGEX to allow only hexadecimal characters:

EditText myTextField = (EditText) findViewById(R.id.myTextView);

InputFilter inputFilterText = new InputFilter() {

    @Override
    public CharSequence filter(CharSequence source, int start, int end, Spanned dest, int dstart, int dend) {

        Pattern patern = Pattern.compile("^\\p{XDigit}+$");

        StringBuilder sb = new StringBuilder();

        for (int i = start; i < end; i++) {

            if (!Character.isLetterOrDigit(source.charAt(i)) && !Character.isSpaceChar(source.charAt(i))                            ) {
                //is not(Letter or Digit or space);
                return "";
            }

            //Only allow characters "0123456789ABCDEF";
            Matcher matcher = patern.matcher(String.valueOf(source.charAt(i)));
            if (!matcher.matches()) {
                return "";
            }

            //Add character to Strinbuilder
            sb.append(source.charAt(i));

            /*counterForSpace++;
            if(counterForSpace>1){
                //Restar counter contador
                counterForSpace = 0;
                //Add space!
                sb.append(" ");
            }*/

        }
        //Return text in UpperCase.
        return  sb.toString().toUpperCase();
    }
};

myTextField.setFilters(new InputFilter[] { inputFilterText });
myTextField.setInputType(InputType.TYPE_TEXT_FLAG_NO_SUGGESTIONS);

both options have as a result:

Check this related answer too:

https://es.stackoverflow.com/a/211240/95