Why isn't (“Maya” == “Maya”) true in C++?

Question

Any idea why I get \"Maya is not Maya\" as a result of this code?

if (\"Maya\" == \"Maya\") 
   printf(\"Maya is Maya \\n\");
else
   printf(\"Maya is not Ma         


        

Answer 1

C and C++ do this comparison via pointer comparison; looks like your compiler is creating separate resource instances for the strings "Maya" and "Maya" (probably due to having an optimization turned off).